How many BTU/h does it take to heat 1 gallon of water from 55F to 120F, given 1 gallon of water weighs 8.33 lbs?

How many BTU/h does it take to heat 1 gallon of water from 55F to 120F, given 1 gallon of water weighs 8.33 lbs?

• A. 450 BTU/h
• B. 541 BTU/h
• C. 600 BTU/h
• D. 700 BTU/h

Answer: (B)

To determine the BTU required to heat 1 gallon of water from 55°F to 120°F, you can use the formula: \[ \text{BTU} = \text{weight of water (lbs)} \times \text{temperature change (°F)} \times \text{specific heat of water (BTU/lb°F)} \] In this calculation, the specific heat of water is approximately 1 BTU/lb°F, the weight of 1 gallon of water is 8.33 lbs, and the temperature change is the difference between 120°F and 55°F, which is: \[ 120°F - 55°F = 65°F \] Now, substituting the values into the formula gives: \[ \text{BTU} = 8.33 \, \text{lbs} \times 65 \, \text{°F} \times 1 \, \text{BTU/lb°F} = 541.45 \, \text{BTU} \] Rounding this value gives approximately 541 BTU, which aligns with the chosen answer. This calculation demonstrates not only how the temperature change and the weight of water interact to

To determine the BTU required to heat 1 gallon of water from 55°F to 120°F, you can use the formula:

[

\text{BTU} = \text{weight of water (lbs)} \times \text{temperature change (°F)} \times \text{specific heat of water (BTU/lb°F)}

]

In this calculation, the specific heat of water is approximately 1 BTU/lb°F, the weight of 1 gallon of water is 8.33 lbs, and the temperature change is the difference between 120°F and 55°F, which is:

[

120°F - 55°F = 65°F

]

Now, substituting the values into the formula gives:

[

\text{BTU} = 8.33 , \text{lbs} \times 65 , \text{°F} \times 1 , \text{BTU/lb°F} = 541.45 , \text{BTU}

]

Rounding this value gives approximately 541 BTU, which aligns with the chosen answer. This calculation demonstrates not only how the temperature change and the weight of water interact to